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0 - SQL=SELECT tag.name, tag.id FROM i07tk_k2_tags as tag LEFT JOIN i07tk_k2_tags_xref AS xref ON xref.tagID = tag.id WHERE xref.itemID IN () AND tag.published = 1 ORDER BY tag.name ASC

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SQL=SELECT tag.name, tag.id FROM i07tk_k2_tags as tag LEFT JOIN i07tk_k2_tags_xref AS xref ON xref.tagID = tag.id WHERE xref.itemID IN () AND tag.published = 1 ORDER BY tag.name ASC